How to make an array using pointers in C++?

#include "stdafx.h"


#include %26lt;iostream%26gt;


using namespace std;





void print (int* a, int* b, int arraySize) {


int* aPtr;


int* bPtr;


int i;





cout %26lt;%26lt; "The values:" %26lt;%26lt; endl;


for (i = 0, aPtr = a, bPtr = b; i %26lt; arraySize;


cout %26lt;%26lt; "A[" %26lt;%26lt; i %26lt;%26lt; "]: " %26lt;%26lt; *(aPtr++) %26lt;%26lt; endl,


cout %26lt;%26lt; "B[" %26lt;%26lt; i %26lt;%26lt; "]: " %26lt;%26lt; *(bPtr++) %26lt;%26lt; endl, i++);


}





int main() {


const int arraySize = 10;


int* a = new int[arraySize];


int* b = new int[arraySize];


int* aPtr;


int* bPtr;


int i;





// initialise


for (i = 0, aPtr = a, bPtr = b; i %26lt; arraySize; *(aPtr++) = 1, *(bPtr++) = 2, i++);





// print


print(a, b, arraySize);





// copy


for (i = 0, aPtr = a, bPtr = b; i %26lt; arraySize; *(aPtr++) = *(bPtr++), i++);





// print


print(a, b, arraySize);


}

How to make an array using pointers in C++?
void main()


{


int i;





int *ar[10];





int num[10];





for( i=0;i%26lt;10;i++)


{





ar[i]=%26amp;(num[i]);


}





for(i=0;i%26lt;10;i++)


{


cout%26lt;%26lt; *(ar[i]);


}


getch();


}
Reply:try this link





http://www.intap.net/~drw/cpp/
Reply:array a[15]


a[0]=9;


a[0]-%26gt;next=a[1]=4;


......


you have to define next before you use it as global variable